[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 20:44:05
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤

[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简
结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤

[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤
3k^2+11k+10
=(3k+5)(k+2)
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2)
=[k(k+1)/12](3k+5)(k+2)+(k+1)(k+2)
=(k+1)(k+2)[k(3k+5)/12+1]
=(k+1)(k+2)[k(3k+5)+12]/12
=(k+1)(k+2)(3k^2+5k+1)/12