作业帮[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值.
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/29 18:46:09
![[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值.](/uploads/image/z/14995229-5-9.jpg?t=%5B%28y%2Ay%2Ay-y%29%2F%28xy%2B1%29%2A%28xy%2B1%29-%28x%2By%29%2A%28x%2By%29%5D%2F%5B%28x%2By%29%2Ay%2F%28x%2B1%29%5D%E5%85%B6%E4%B8%ADx%3D-11%2Cy%3D1%2F12%2C%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BC.)
[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值.
[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值.
[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值.
原式=[y(y+1)(y-1)/(xy+1+x+y)(xy+1-x-y)]*[(x+1)/u(x+y)]
=[y(y+1)(y-1)/(x+1)(y+1)(x-1)(y-1)]*[(x+1)/y(x+y)]
=[y/(x+1)(x-1)]*[(x+1)/y(x+y)]
=1/(x-1)(x+y)
=1/131
(b+1)/(a-b) - b/a通分
=(ab+a-ab+b^2)/a(a-b)
=(a+b^2)/a(a-b)
a<0
a
所以a+b^2符号无法判断
比如a=-2,b=-1,则a+b^2<0
而a=2,b=-1.5,则a+b^2>0
所以符号无法判断
xy-1+x-y
证明:(y/x)+(x/y)+xy≥x+y+1
（x+y)*（x+1)-(xy+y*y)因式分解为多少
(x+y)(x—y)y(xy+1)
[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值.
|x|/x+y/|y|+xy/|xy|=
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
1/x-1/y=x,求5y+xy-5y/y-xy-x=?
xy-x-y+1/y²-2y+1
y平方-2y+1分之xy-x-y-1
{(x-y/x^2-2xy+y^2)-(xy+y^2/x^2-y^2)}*(xy/y-1)
.(x+y-2)(x+y-2xy)+(xy-1)^2
因式分解xy-x-y+1
xy+x+y+1因式分解
1-x-y+xy 因式分解
因式分解:xy+x+y+1
xy-1+x-y因式分解
xy-x-y+1因式分解