line(x1 15,y1 5,x2-15,y1 5);r==2)iArray[pt->LL,IDC_ARROW);chievedthetargetedsales\n");

line(x1 15,y1 5,x2-15,y1 5);r==2)iArray[pt->LL,IDC_ARROW);chievedthetargetedsales ); line(x1 5,y1 15,x1 15,y1 5);maxIdx=0;/*paintthecursorwhenibackup->LeftChild=temp; a[N-i-1]=temp;printf( sortedarray: );line(x1 5,y2-15,x1 5,y1 15);fgets(str,strlen(str) 1,fp);scanf(%d, vb中,scale(0,600)-(600,0)和line(x1,y1)-(x2, mathematica manipulate命令使用使用小弟初学mathematica,有些问题想请教下大哥大姐们.x =.; y =.x1 = 2; y1 = 0;x2 = 0; y2 = -1;ob = Graphics[Line[{{x1,y1},{x2,y2 - a}}],Axes -> True] /.a -> 1;eq1 = (y - y1)/(x - x1) == (y - y2 + a)/ printf(deleteitemdetails );是系统进程line(x2-1,y2-11,x2-1,y1 11); matlab如何将一组数代入原方程的字母里?syms x1 x2 x3 x4 y1 y2 y3 y4 X1 X2 X3 X4 Y1 Y2 Y3 Y4A=[x1,y1,1,0,0,0,-x1*X1,-y1*X1;0,0,0,x1,y1,1,-x1*Y1,-y1*Y1;x2,y2,1,0,0,0,...-x2*X2,-y2*X2;0,0,0,x2,y2,1,-x2*Y2,-y2*Y2;x3,y3,1,0,0,0,-x3*X3,-y3*X3; 计算机图形学：Matlab编程画直线（DDA算法）DDA-line(x1,y1,x2,y2,color) int x1, y1,x2,y2,color; { int length; float x, y,x,y ; length =abs(x2-x1); if (abs(y2-y1)>length)length=abs(y2-y1); x=(x2-x1)/length; 求x^3-15x^2+16x-80一个实根,下面程序怎么算不出来#include#includefloat f(float x){return ((x-5)*x-16)*x-80;}float xpoint(float x1,float x2){return (x1*f(x2)-x2*f(x1))/(f(x2)-f(x1));}float root(float x1,float x2){float x,y,y1;y1=f(x1);do{ MATLAB解方程、绘图问题y1 =(4*x1)/5 + x2/3 - x1*((4*x2)/3 - 4/5) - (4*x1*x2)/3 - 1/2y2 =x1/2 + (4*x2)/5 - x2*((3*x1)/2 - 4/5) - (3*x1*x2)/2 - 1/2我想令y1=0,解出x1（是x2的函数）；令y2=0,解出x2（式x1的函数）.解出方程之 matlab画出雪花曲线function y=koch(x1,x2,y1,y2,n)if n>1koch(x1,y1,(2*x1+x2)/3,(2*y1+y2)/3,n-1);koch((2*x1+x2)/3,(2*y1+y2)/3,(x1+x2)/2+(y1-...y2)*sqrt(3)/6,(y1+y2)/2+(x2-x1)*sqrt(3)/6,n-1);koch((x1+x2)/2+(y1-y2)*sqrt(3)/6,(y1+y2)/2+(x2-...x1)*sqr 已知两组数x1,x2,…xn和y1,y2,…yn,他们的平均数分别是“x拔”,“y拔”,分别求下列各组新数据的（1）5x1,5x2,…,5xn；（2）x1-y1,x2-y2,…,xn-yn；（3）x1,y1,x2,y2,…,xn,yn． line(x1 1,y1 11,x1 11,y1 1);printf(Sorry!Nodatacanbefound );putimage(x,y,logoBmp2,method);labellevel->setText(Level:); 在LINGO中如何将整数输入min 100x1+100x2+40y1+40y2+40y3+40y4+40y5stx1+x2+y1>=4x1+x2+y1+y2>=3x1+x2+y1+y2+y3>=4x2+y1+y2+y3+y4>=6x1+y2+y3+y4+y5>=5x1+x2+y3+y4+y5>=6x1+x2+y4+y5>=8x1+x2+y5>=8y1+y2+y3+y4+y5 mathematica线性规划Maximize[18x1+10x1+30x2-30x3+48x3-2y1-3y2-5x1-4x2-x3,{y1 VB line函数用法picturebox控件里有个line函数object.Line [Step] (x1,y1) [Step] - (x2,y2),[color],[B][F] 我想问的是最后的[B][F]什么意思,怎么用最好举个例子说明, MATLAB 已知3点求夹角>> x1=1;y1=1;x2=0;y2=0;x3=0;y3=3;theta=acosd(dot([x1-x2,y1-y2],[x3-x2,y3-y2])/(norm([x1-x2,y1-y2])*norm([x1-x2,y3-y2])))theta =47.8696>> x1=1;y1=1;x2=0;y2=0;x3=0;y3=3;theta=acos(dot([x1-x2,y1-y2],[x3-x2,y3-y2])/(norm([x1-x2, 数列1,x1,x2,...x7,5和数列1,y1,y2,...y6,5均成等差数列,公差分别是d1,d2,求d1/d2与x1+x2+...+x7/y1+y2+...+y6的值