x^+10x+4y^+4y+26=0求x、y的值?

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x^+10x+4y^+4y+26=0求x、y的值?
x^+10x+4y^+4y+26=0求x、y的值?

x^+10x+4y^+4y+26=0求x、y的值?
x^2+10x+4y^2+4y+26=0
化简得（x+5）^2+（2y+1）^2=0
因为任何数的平方非负
所以x+5=0,2y+1=0
得到x=-5,y=-1/2

(x+5)^2+(2y+1)^2=0
因为两个平方都是大于等于0的，所以只能都等于0
所以x=-5,y=-1/2

(x²+10x+25)+(4y²+4y+1)=0
(x+5)²+(2y+1)²=0
x=-5,y=-1/2

x^+10x+4y^+4y+26
=(x+5)^2+(2y+1)^2=0
故x+5=0 2y+1=0
所以 x=-5 y=-1/2

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