化简sin(2x-pi)sin[x+(3/2)pi]/cos[x+(5/2)pi][1-sin(pi+x)]

化简sin(2x-pi)sin[x+(3/2)pi]/cos[x+(5/2)pi][1-sin(pi+x)] 化简sin(x+PI/3)+2sin(x-PI/3)-根号3*cos(2pi/3-1) 由sin(-3x-pi/2)是否等于-sin(3x+pi/2) y=sin(x+pi/3)sin(x+pi/2)的最小正周期是什么 已知sin(x+pi/6)=1/4,求sin（5pi/6-x)+sin^2(pi/3-x)的值 sin(x+PI/2)怎么算啊 f(2x)=sin (x+3*pi/4)+cos (x-pi/2), f(x)＝2sin(x-pi/6)sin(x＋pi/3) 求最小正周期 sin(3x+pi/3)的周期pi是派 sinx/(3+sin^2x)dx0到pi/2 y=sinxy=2sin(x/3+pi/6) 已知Sin(2x+pi/3)=1/3,求Sin(5Pi/6-4x),用三角变换 matlab中is not a valid expression or equation.x=solve('2/3*14.3*pi*500^3*(sin(x*pi))^3/pi-(sin(pi*x)+sin((1.25-2*x)*pi))*450*x*14.3*pi*500^2*(1-sin(2*pi*x)/(2*pi*x))/(pi*(3x-1.25)）=402.86','x')Error using ==> solve' 2/3*14.3*pi*500^3*(sin(x*pi))^3 sin(2x+pi/3)=cos(2x-pi/6) 成立吗 y=sin(2x+Pi/3)+cos(Pi/6-2x)周期为 f(x)=2sin^2(pi/4+x)-√3cos2x化简 谢谢 急!matlab,求大神解答x=solve('9530*(sin(pi*x)^3)/pi+14300*x*(1-sin(2*pi*x)/(2*pi*x))/(1.25-3*x)*(sin(pi*x)+sin(pi*(1.25-2*x))/pi-983.04=0','x')想求解这个含三角函数的一元三次方程,但显示Error using ==> solve is not a valid expr MATLAB z=100000*sin(y*pi/180)/(17*sqrt(3+sin(2*x*pi/180)));是不是缺几个点