作业帮在线求一道英语数学题,有关 logistic growth function.The logistic growth function f(t) = 3150/ 1+6e^(-0.22t) describes the population of a species of butterflies t months after they are introduced into a non-threatening habitat.(a) Who many
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在线求一道英语数学题,有关 logistic growth function.The logistic growth function f(t) = 3150/ 1+6e^(-0.22t) describes the population of a species of butterflies t months after they are introduced into a non-threatening habitat.(a) Who many
在线求一道英语数学题,有关 logistic growth function.
The logistic growth function f(t) = 3150/ 1+6e^(-0.22t) describes the population of a species of butterflies t months after they are introduced into a non-threatening habitat.
(a) Who many butterflies were initially introduced into the habitat?
(b) In how many months will the number of butterflies be five times as large as the initial number?
(c) According to the function,how may butterflies will there be after a long time has elapsed?
Round off your answers to the nearest whole numbers.
(a) 450 这个我会做
(b) 约等于 12 months
(c) 3150
求 b 和 c 我对这个题还不是很理解.
在线求一道英语数学题,有关 logistic growth function.The logistic growth function f(t) = 3150/ 1+6e^(-0.22t) describes the population of a species of butterflies t months after they are introduced into a non-threatening habitat.(a) Who many
(a)
f(t) = 3150/ 1+6e^(-0.22t) 令t=0 得the initial number=450
(b)
f(t) = 3150/ [1+6e^(-0.22t) ]=5*450 解得t=(ln15)/0.22=12.31months
(c)
t→+∞时,lim f(t)=3150/ [1+6*lime^(-0.22t) ]=3150/ (1+0)=3150