若 x^2+y-2*根号y+2x+2=0 ,求实数x和y的值各是多少.

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若 x^2+y-2*根号y+2x+2=0 ,求实数x和y的值各是多少.

若 x^2+y-2*根号y+2x+2=0 ,求实数x和y的值各是多少.
若 x^2+y-2*根号y+2x+2=0 ,求实数x和y的值各是多少.

若 x^2+y-2*根号y+2x+2=0 ,求实数x和y的值各是多少.
x^2+y-2√y+2x+2=0
(x^2+2x+1)+(y-2√y+1)=0
(x+1)^2+(√y-1)^2=0
所以x+1=0,√y-1=0
x=-1,y=1

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