设f(x)=|x-1|,x≥1,f(x)=2x-3/x,x<1 ,解不等式f(x)-1≥0.

设f(x)=1/x(x 设f(x)=1-x,(x 设函数f(x)=x-[x],x≥0,f(x+1),x 设f(x)=lgx,证明f(x)+f(x+1)=f[x(x+1)] 设函数f(x)满足f(x)+2f(1/x)=x,求f(x) 设f(x)= 1-x分之x 求f[(fx)]和f{f[f(x)]} 设f(x)满足f(1/x)=x/1-x设设f(x)满足f(1/x)=x/1-x ,则f(x+1)=? 设函数f(x)={(1/2)^x(x≥4),f(x+3)(x 设函数f(x)=(1/2）^x(x≥4), f(x)=f(x+3)(x 设f(x+ 1/x)=x²+ 1/x²,求f(x),f(sinx) 设f(x)+f(x-1／x)=2x,求f(x)=? 设f(x)={3x-1,x=0,求f(-x),f(x-2). 设f(x)=(x平方-1)/(x-1) (x 设f(x)=(x平方-1)/(x-1) (x 设f(x)=x/2+1/x(x 设f(x)={1+x (-1 设f(x)={1+x (-1 设f(x){e^(1/x),x