若x^2-2x+10+y^2+6y=0,求（2x-y）^2 的值如题

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若x^2-2x+10+y^2+6y=0,求（2x-y）^2 的值如题
若x^2-2x+10+y^2+6y=0,求（2x-y）^2 的值
如题

若x^2-2x+10+y^2+6y=0,求（2x-y）^2 的值如题
x^2-2x+10+y^2+6y=0
x^2-2x+1+y^2+6y+9=0
=(x-1)^2+(y+3)^2=0
x-1=0,y+3=0
x=1,y=-3
（2x-y）^2
=(2+3)^2
=5^2
=25

已知可写成(x-1)平方+(y+3)平方=0.所以x=1.y=-3最后结果为25

首先可以吧10拆成是9+1 就会有x^2-2x+1y^2+6y+9=0,根据完全平方公式得（X-10）^2+（Y+3）^2=O 解出X=1 Y=-3 所以代入（2x-y）^2得出值为2×1+3的平方等于 25

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