已知a属于(0,π/2),且2(sina)^2-sinacosa-3(cosa)^2=0,求sin(a+π/4)/(sin2a+cos2a+1)的值.

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已知a属于(0,π/2),且2(sina)^2-sinacosa-3(cosa)^2=0,求sin(a+π/4)/(sin2a+cos2a+1)的值.

已知a属于(0,π/2),且2(sina)^2-sinacosa-3(cosa)^2=0,求sin(a+π/4)/(sin2a+cos2a+1)的值.
已知a属于(0,π/2),且2(sina)^2-sinacosa-3(cosa)^2=0,求sin(a+π/4)/(sin2a+cos2a+1)的值.

已知a属于(0,π/2),且2(sina)^2-sinacosa-3(cosa)^2=0,求sin(a+π/4)/(sin2a+cos2a+1)的值.
2(sina)^2-sinacosa-3(cosa)^2=0,(2sinα-3)(sinα+1)=0,sinα=-1(sinα=3/2舍去)
sin(a+π/4)/(sin2a+cos2a+1)=sin(a+π/4)/(sin2a+2cos²a)
=(sinαcosπ/4+cosαsinπ/4)/[2sinα(sinα+cosα)]=(√2/2)÷(-2)=-√2/4