求证:tana/2=sina/1+cosa=1-cosa/sina

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求证:tana/2=sina/1+cosa=1-cosa/sina

求证:tana/2=sina/1+cosa=1-cosa/sina
求证:tana/2=sina/1+cosa=1-cosa/sina

求证:tana/2=sina/1+cosa=1-cosa/sina
tan(a/2)
=sin(a/2)/cos(a/2)
=2sin(a/2)cos(a/2)/[2cos^(a/2)]
=sina/(1+cosa)
=sina(1-cosa)/(1-cos^a)
=sia(1-cosa)/sin^a
=(1-cosa)/sina.