作业帮√[﹙lg3﹚³-lg9+1﹙lg√27+lg8-lg√1000﹚]/lg0.3lg1.2
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/09 13:18:00
![√[﹙lg3﹚³-lg9+1﹙lg√27+lg8-lg√1000﹚]/lg0.3lg1.2](/uploads/image/z/10885184-8-4.jpg?t=%E2%88%9A%5B%EF%B9%99lg3%EF%B9%9A%26%23179%3B-lg9%2B1%EF%B9%99lg%E2%88%9A27%2Blg8-lg%E2%88%9A1000%EF%B9%9A%5D%2Flg0.3lg1.2)
√[﹙lg3﹚³-lg9+1﹙lg√27+lg8-lg√1000﹚]/lg0.3lg1.2
√[﹙lg3﹚³-lg9+1﹙lg√27+lg8-lg√1000﹚]/lg0.3lg1.2
√[﹙lg3﹚³-lg9+1﹙lg√27+lg8-lg√1000﹚]/lg0.3lg1.2
√[﹙lg3﹚^2-lg9+1]*﹙lg√27+lg8-lg√1000﹚]/lg0.3lg1.2
=√(lg3-1)^2*(3/2*lg3+3lg2-3/2)/(lg3-1)(lg12-1)
=(1-lg3)*3/2(lg3+2lg2-1)/[(lg3-1)(lg3+2lg2-1)]
=-3/2
=-1.5
√[(lg3)^2-lg9+1]=√(lg3-1)^2=1-lg3
lg√27+lg8-lg√1000=3/2*lg3+3lg2-3/2=3/2(lg3+2lg2-1)
lg0.3*lg1.2=(lg3-1)(lg12-1)=(lg3-1)(lg3+2lg2-1)
1.5