作业帮先化简,再求值:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/14 13:13:09
![先化简,再求值:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1](/uploads/image/z/1024486-70-6.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%2C%E5%86%8D%E6%B1%82%E5%80%BC%3A%5B%28x%26%23178%3B-2x%2B1%29%E5%88%86%E4%B9%8Bx%5D%C3%B7%5B%28x%26%23178%3B-1%29%E5%88%86%E4%B9%8B%28x%2B1%29%2B1%5D%2C%E5%85%B6%E4%B8%ADx%3D%E6%A0%B9%E5%8F%B72%2B1)
先化简,再求值:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1
先化简,再求值:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1
先化简,再求值:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1
:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1
=[x/(x-1)²]÷[(x+1)/(x-1)(x+1)+1]
=[x/(x-1)²]÷[1/(x-1)+1]
=[x/(x-1)²]÷[(1+x-1)/(x-1)]
=[x/(x-1)²]÷[x/(x-1)]
=1/(x-1)
=1/(√2+1-1)
=1/(√2)
=(√2)/2